[Oct 08, 2026] Fully Updated Dumps PDF - Latest 1z0-071 Exam Questions and Answers
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The Oracle 1z0-071 exam covers a wide range of topics related to SQL and database management, including basic SQL concepts, data retrieval using SELECT statements, data manipulation using DML statements, table creation and management, and database security. It is designed for individuals who have a basic understanding of SQL and relational database concepts, and who want to improve their skills and knowledge in managing Oracle databases.
NEW QUESTION # 257
View the Exhibit and examine the description of the tables.
You execute this SQL statement:
Which three statements are true?
- A. The statement will fail if a row already exists in the SALES table for product 23.
- B. The statement will execute successfully and a new row will be inserted into the SALES table.
- C. A product can have a different unit price at different times.
- D. The SALES table has five foreign keys.
- E. A customer can exist in many countries.
- F. The statement will fail because a subquery may not be contained in a VALUES clause.
Answer: B,D,E
NEW QUESTION # 258
View the Exhibits and examine PRODUCTSand SALES tables.
Exhibit 1
Exhibit 2
You issue the following query to display product name the number of times the product has been sold:
What happens when the above statement is executed?
- A. The statement produces an error because a subquery in the FROMclause and outer-joins cannot be used together.
- B. The statement produces an error because ITEM_CNTcannot be displayed in the outer query.
- C. The statement produces an error because the GROUP BYclause cannot be used in a subquery in the FROMclause.
- D. The statement executes successfully and produces the required output.
Answer: D
NEW QUESTION # 259
Examine the structure of the INVOICEtable.
Which two SQL statements would execute successfully?
SELECT inv_no, NVL2(inv_date, 'Pending', 'Incomplete')
- A. FROM invoice;
SELECT inv_no, NVL2(inv_date, sysdate-inv_date, sysdate) - B. FROM invoice;
- C. FROM invoice;
SELECT inv_no, NVL2(inv_amt, inv_date, 'Not Available') - D. FROM invoice;
SELECT inv_no, NVL2(inv_amt, inv_amt*.25, 'Not Available')
Answer: C,D
NEW QUESTION # 260
Which three statements are true about time zones, date data types, and timestamp data types in an Oracle database?
- A. The SESSIONTIMEZONE function can return an offset from Universal Coordinated Time (UTC)
- B. The DBTIMEZONE function can return an offset from Universal Coordinated Time (UTC)
- C. The CURRENT_TIMESTAMP function returns data without time zone information
- D. A TIMESTAMP data type column contains information about year, month, and day
- E. A TIMESTAMP WITH LOCAL TIMEZONE data type column is stored in the database using the time zone of the session that inserted the row
Answer: A,B,E
NEW QUESTION # 261
Evaluate the following statement.
Which statement is true regarding the evaluation of rows returned by the subquery in the INSERT statement?
- A. They are evaluated by the first WHEN clause. If the condition is true, then the row would be evaluated by the subsequent WHEN clauses.
- B. They are evaluated by the first WHEN clause. If the condition is false, then the row would be evaluated by the subsequent WHEN clauses.
- C. The insert statement would give an error because the ELSE clause is not present for support in case none of WHEN clauses are true.
- D. They are evaluated by all the three WHEN clauses regardless of the results of the evaluation of any other WHEN clause.
Answer: D
Explanation:
Explanation
References:
http://psoug.org/definition/WHEN.htm
NEW QUESTION # 262
Which two statements are true about conditional INSERT ALL?
- A. Each WHEN condition is tested for each row returned by the subquery.
- B. Each row returned by the subquery can be inserted into only a single target table.
- C. The total number of rows inserted is always equal to the number of rows returned by the subquery
- D. A single WHEN condition can be used for multiple INTO clauses.
- E. It cannot have an ELSE clause.
Answer: A,D
Explanation:
For conditional INSERT ALL in Oracle Database 12c:
* D. A single WHEN condition can be used for multiple INTO clauses. This is true. A single WHEN condition in a multi-table insert can direct the insertion of a single row source into multiple target tables.
* E. Each WHEN condition is tested for each row returned by the subquery. True, each row from the subquery is evaluated against each WHEN condition to determine into which table(s) the row should be
* inserted.
Options A, B, and C are incorrect:
* A is incorrect because a row can indeed be directed into multiple tables based on the conditions.
* B is incorrect as INSERT ALL can include an ELSE clause to handle rows that do not meet any of the specified conditions.
* C is incorrect because not every row from the subquery necessarily results in a row insertion; it depends on the conditions being met.
NEW QUESTION # 263
View the exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement?
- A. finding the number of customers, in each city, who's marital status is 'married'.
- B. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
- C. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
- D. listing of customers who do not have a credit limit and were born before 1980
- E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
Answer: C,E
NEW QUESTION # 264
Examine this Statement which returns the name of each employee and their manager, SELECT e.last name AS emp,,m.last_name AS mgr FROM employees e JOIN managers m ON e.manager_ id = m. employee_ id ORDER BY emp; You want to extend the query to include employees with no manager. What must you add before JOIN to do this?
- A. CROSS
- B. LEFT OUTER
- C. FULL OUTER
- D. RIGHT OUTER
Answer: B
Explanation:
To include employees with no manager in the query results, a LEFT OUTER JOIN should be used. This type of join returns all records from the left table (employees), and the matched records from the right table (managers). The result is NULL from the right side if there is no match.
Here's the modified query:
SELECT e.last_name AS emp, m.last_name AS mgr FROM employees e LEFT OUTER JOIN managers m ON e.manager_id = m.employee_id ORDER BY emp; This ensures that even if an employee does not have a manager (i.e., e.manager_id is NULL or there is no corresponding m.employee_id), that employee will still be included in the results.
NEW QUESTION # 265
Which two queries execute successfully?
- A. SELECT NULLIF(100, 'A') FROM DUAL
- B. SELECT NULLIF(NULL, 100) FROM DUAL
- C. SELECT CO ALESCE(100, 'A' ) FROM DUAL
- D. SELECT COALESCE(100, NULL, 200) FROM DUAL
- E. SELECT NULLIF(100, 100) FROM DUAL
Answer: B,C,D,E
Explanation:
The NULLIF and COALESCE functions in Oracle SQL serve specific purposes:
* Option A: Executes successfully. NULLIF returns NULL if the two arguments are equal; otherwise, it
* returns the first argument.
* Option B: Also correct. COALESCE returns the first non-null value among its arguments.
* Option C: This will not execute successfully because NULLIF requires both arguments to be of comparable data types. Comparing an integer to a character ('100' to 'A') is invalid.
* Option D: Executes successfully. NULLIF returns NULL because it compares NULL to a number, which is valid (though always yields NULL).
* Option E: Executes successfully. COALESCE accepts any data type as it returns the first non-null value, irrespective of type consistency among the arguments.
NEW QUESTION # 266
View the Exhibits and examine PRODUCTS and SALES tables.
Exhibit 1
Exhibit 2
You issue the following query to display product name the number of times the product has been sold:
What happens when the above statement is executed?
- A. The statement produces an error because the GROUP BY clause cannot be used in a subquery in the FROM clause.
- B. The statement produces an error because a subquery in the FROM clause and outer- joins cannot be used together.
- C. The statement produces an error because ITEM_CNT cannot be displayed in the outer query.
- D. The statement executes successfully and produces the required output.
Answer: D
NEW QUESTION # 267
Which two statements are true regarding the COUNTfunction? (Choose two.)
- A. COUNT(inv_amt)returns the number of rows in a table including rows with NULLin the INV_AMTcolumn.
- B. It can only be used for NUMBERdata types.
- C. A SELECTstatement using the COUNTfunction with a DISTINCTkeyword cannot have a WHEREclause.
- D. COUNT(DISTINCT inv_amt)returns the number of rows excluding rows containing duplicates and NULLsin the INV_AMTcolumn.
- E. COUNT(*)returns the number of rows including duplicate rows and rows containing NULLvalue in any column.
Answer: D,E
Explanation:
Explanation/Reference:
NEW QUESTION # 268
Which two statements are true about Oracle synonyms? (Choose two.)
- A. A synonym can have a synonym.
- B. Any user can create a PUBLIC synonym.
- C. All private synonym names must be unique in the database.
- D. A synonym can be created on an object in a package.
- E. A synonym has an object number.
Answer: A,E
Explanation:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_7001.htm
NEW QUESTION # 269
Which two statements are true about a self join?
- A. It can be a left outer join.
- B. It can be an inner join.
- C. It must be an equijoin.
- D. The join key column must have an index.
- E. It must be a full outer join.
Answer: A,B
NEW QUESTION # 270
Which two tasks can be performed by using Oracle SQL statements? (Choose two.)
- A. querying data from tables in different databases
- B. starting up a database instance
- C. changing the password for an existing database user
- D. connecting to a database instance
- E. executing operating system (OS) commands in a session
Answer: A,C
Explanation:
References:
http://www.techonthenet.com/oracle/password.php
https://docs.oracle.com/cd/B28359_01/server.111/b28324/tdpii_distdbs.htm
NEW QUESTION # 271
Which two statements are true regarding roles? (Choose two.)
- A. A role can be granted to PUBLIC.
- B. Roles are named groups of related privileges that can be granted to users or other roles.
- C. A user can be granted only one role at any point of time.
- D. The REVOKE command can be used to remove privileges but not roles from other users.
- E. A role can be granted to itself.
Answer: A,B
Explanation:
References:
http://docs.oracle.com/cd/E25054_01/network.1111/e16543/authorization.htm#autoId28
NEW QUESTION # 272
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTSand TIMEStables.
The PROD_IDcolumn is the foreign key in the SALEStable referencing the PRODUCTStable.
The CUST_IDand TIME_IDcolumns are also foreign keys in the SALEStable referencing the CUSTOMERS and TIMEStables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?
- A. The NEW_SALEStable would get created and all the NOTNULLconstraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
- B. The NEW_SALEStable would not get created because the column names in the CREATETABLE command and the SELECTclause do not match.
- C. The NEW_SALEStable would get created and all the FOREIGNKEYconstraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
- D. The NEW_SALEStable would not get created because the DEFAULTvalue cannot be specified in the column definition.
Answer: A
NEW QUESTION # 273
Examine this statement which executes successfully:
Which statement will violate the CHECK constraint?
- A. SELECT *
FROM emp80
WHERE department_id=80 - B. SELECT *
FROM emp80
WHERE department_id=90; - C. UPDATE emp80
SET department_id=90
WHERE department_id=80; - D. DELETE FROM emp80
WHERE department_id=90;
Answer: C
Explanation:
The CHECK constraint is generally used to limit the range of values that can be placed in a column. If a CHECK constraint exists on the department_id to only allow values such as 80 (assuming from the context provided):
* A. UPDATE emp80 SET department_id=90 WHERE department_id=80: This UPDATE statement attempts to set the department_id to 90 for rows where it is currently 80. If there is a CHECK constraint preventing department_id from being anything other than 80, this statement would violate that constraint.
Incorrect options:
* B: DELETE operations do not affect CHECK constraints as they do not involve modifying or setting column values.
* C and D: SELECT statements do not modify data and thus cannot violate data integrity constraints like CHECK constraints.
NEW QUESTION # 274
Which two statements are true about the results of using the intersect operator in compound queries?
- A. Column names in each select in the compound query can be different.
- B. Reversing the order of the intersected tables can sometimes affect the output.
- C. The number of columns in each select in the compound query can be different.
- D. intersect ignores nulls.
- E. intersect returns rows common to both sides of the compound query.
Answer: A,E
NEW QUESTION # 275
The following are the steps for a correlated subquery, listed in random order:
1) The WHERE clause of the outer query is evaluated.
2) The candidate row is fetched from the table specified in the outer
query.
3) The procedure is repeated for the subsequent rows of the table, till all the rows are processed.
4) Rows are returned by the inner query, after being evaluated with the value from the candidate row in the outer query.
Identify the option that contains the steps in the correct sequence in which the Oracle server evaluates a correlated subquery.
- A. 4,1,2,3
- B. 2,4,1,3
- C. 4,2,1,3
- D. 2,1,4,3
Answer: B
NEW QUESTION # 276
Examine the description or the BOOKS_TRANSACTIONS table:
FOR customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?
- A. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level IS NOT NULL
AND due_amount IS NOT NULL; - B. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND cust credit_level !=NULL; - C. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level <> NULL
AND due_amount <> NULL; - D. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust income_level !=NULL
AND due_amount !=NULL; - E. SELECT cust_first_name, cust_credit_limit * . 05 AS DUE AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL
AND cust_credit_limit IS NOT NULL;
Answer: E
Explanation:
D: True. This query selects the first name and calculates the due amount as 5% of the credit limit from the customers table where the income level is not null and the credit limit is also not null. The IS NOT NULL operator is used to check for non-null values correctly.
The IS NOT NULL operator is the correct way to check for non-null values in SQL. The <> NULL and != NULL comparisons are incorrect because NULL is not a value that can be compared using these operators; it represents the absence of a value.
There is no due_amount column in the customers table according to the structure provided, so any WHERE clause referencing due_amount is irrelevant and incorrect. The due_amount is a derived column in the SELECT clause.
The correct syntax to check for non-null values is IS NOT NULL, which is used in the WHERE clause of the correct answer.
Reference:
The use of IS NOT NULL in the WHERE clause to filter out null values is documented in Oracle's SQL reference.
NULL comparisons must be done with IS NULL or IS NOT NULL for correct logical evaluation in SQL.
NEW QUESTION # 277
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